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A thin, uniform rod is bent into a square of side length

**a**. If the total mass is

**M**, find the moment of inertia about an axis through the center and perpendicular to the plane of the square. Use the parallel-axis theorem.

TIA.

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- Thread starter Iron Eagle
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- #1

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A thin, uniform rod is bent into a square of side length

TIA.

- #2

Doc Al

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- #3

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I = (1/12)*M*(a^2+b^2)

1. Simply, for a square it would just be (a^2+a^2) or (2a^2)

2. Then, we find moment of inertia from the parallel-axis theorem.

3. Finally, take the moment of inertia from the parallel-axis theorem and subtract.

(so, parallel-axis - moment of inertia)

4. That's it, that should be the answer.

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